Question
Pipe A can fill the empty tank in 25 minutes while pipe
B can empty the half-filled same tank in 15 minutes. What is the time require to fill (80/3) % of the tank when both pipes are opened together ?Solution
Let B can empty the tank in = 15 x 2 =30 minutes Let the capacity of a tank be LCM of (25,30)=150 Pipe A efficiency = 150/25 = 6 units/min Pipe B efficiency = 150/30 = 5 unit/min Therefore, required time to fill (80/3)% of the tank when both pipes are opened together is = (4/15) x 150/(6-5) = 40 minutes
√(3x-2)+ √(3x+2) = 4+ 2√5 then value of x is.
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