Question
‘A’ and ‘B’ can do a piece of work in 16 days
and 24 days, respectively. ‘A’ started working alone and was replaced by ‘B’ after 8 days. In how many days can ‘B’ complete the remaining amount of work alone?Solution
Let the total work be 48 units (LCM of 16 and 24) Efficiency of ‘A’ = 48/16 = 3 units/day Efficiency of ‘B’ = 48/24 = 2 units/day Let the number of days taken by ‘B’ to finish the remaining amount of work be ‘x’ ATQ, (3 × 8) + 2x = 48 Or, 2x = 48 – 24 Or, 2x = 24 Or, x = 24/2 = 12 Therefore, time taken by ‘B’ to complete the remaining work alone = 12 days
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