Question
‘A’ and ‘B’ can do a piece of work in 16 days
and 24 days, respectively. ‘A’ started working alone and was replaced by ‘B’ after 8 days. In how many days can ‘B’ complete the remaining amount of work alone?Solution
Let the total work be 48 units (LCM of 16 and 24) Efficiency of ‘A’ = 48/16 = 3 units/day Efficiency of ‘B’ = 48/24 = 2 units/day Let the number of days taken by ‘B’ to finish the remaining amount of work be ‘x’ ATQ, (3 × 8) + 2x = 48 Or, 2x = 48 – 24 Or, 2x = 24 Or, x = 24/2 = 12 Therefore, time taken by ‘B’ to complete the remaining work alone = 12 days
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
? * 7.05 = (360.06 ÷ 11.02) % of 4290 - 759.91
(10.98% of 499.99) - 4.998 = √?
(56.04% of 550.06 + 19.92 × 18.13) – 121.97 = ?
Two trains, 'P' and 'Q', are moving with speeds of 16 m/s and 24 m/s, respectively. The lengths of the trains are in the ratio 3:...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
8.992 + (5.01 × 4.98) + ? = 224.03
14.2% of 7200 + 2.8% of 6400 =?
319.995 × 15.98 ÷ 4.002 - ? × 7.95 = 1679.89 ÷ 2.005
