Question
βAβ and βBβ can do a piece of work in 16 days
and 24 days, respectively. βAβ started working alone and was replaced by βBβ after 8 days. In how many days can βBβ complete the remaining amount of work alone?Solution
Let the total work be 48 units (LCM of 16 and 24) Efficiency of βAβ = 48/16 = 3 units/day Efficiency of βBβ = 48/24 = 2 units/day Let the number of days taken by βBβ to finish the remaining amount of work be βxβ ATQ, (3 Γ 8) + 2x = 48 Or, 2x = 48 β 24 Or, 2x = 24 Or, x = 24/2 = 12 Therefore, time taken by βBβ to complete the remaining work alone = 12 days
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