Question
Pipe βXβ alone can fill a tank in 20 hours. When
both pipes βXβ and βYβ are opened together, they can fill 75% of the tank in 9 hours. How much time will pipe βYβ alone take to fill 80% of the same tank?Solution
ATQ,
Time taken by pipes βXβ and βYβ together to fill 100% of the tank = 9 Γ· 0.75 = 12 hours
Let the capacity of the tank be 60 litres. {LCM (20 and 12)}
Efficiency of pipe βXβ = (60/20) = 3 litres/hour
Efficiency of pipe βXβ and βYβ together = (60/12) = 5 litres/hour
Efficiency of pipe βYβ = 5 β 3 = 2 litres/hour
Time taken by pipe βYβ to fill 80% of the tank = (60 Γ 0.8)/2 = 24 hours
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