Let the capacity of the cistern = 60 units Then, efficiency of pipe ‘A’ = 60/10 = 6 units/minute Efficiency of pipe ‘B’ = 60/12 = 5 units/minute Efficiency of pipe ‘C’ = 60/12 = 5 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 6 + 5 – 5 = 6 units/minute 50% of the cistern’s capacity = 30 units Therefore, time taken by all 3 pipes together to fill 50% of the cistern = 30/6 = 5 minutes
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