Question
Tap A can fill a tank in 20 hours and tap B can emptied
it is 25 hours. Tap A starts filling and they opened for 1 hour each alternatively in what time will the tank be full?Solution
Let tank capacity is = 100 ltr LCM of 20 and 25 So tap A can fill it in 20 hours ∴ Tap A can fill per hours = 100/20 = 5 ltr Tap B can emptied it in 25 hours ∴ Tap B can empty per hours = 100/25 = 4 ltr Tank filled after 2 hour = 5 - 4 = 1 ltr (If taps open alternatively) In last hour tap A fill tank 5 ltr So rest part of tank need to be filled is = 100 - 5 = 95 ltr In 2 hours tank filled = 1 ltr So 95 ltr to be filled in = 95 × 2 = 190 ∴ So total time = 190 + 1 = 191 hours
√10404 + √9604 - ∛1728 - ∛42875 = ?
1299.999 ÷ 325.018 × 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = √324
(160 × 12 - 13 × 20)/(120 × 2 + 2 × 35 + 2 × 11) = ?