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ATQ, Let the capacity of the tank be 72 units (LCM of 18 and 36). Efficiency of pipes (A + B) = 72/18 = 4 units/hour. Efficiency of pipe ‘B’ = 72/36 = 2 units/hour. Efficiency of pipe ‘A’ = 4 - 2 = 2 units/hour. Time taken by pipe ‘A’ = 72/2 = 36 hours. Time taken by pipe ‘C’ = 36 - 12 = 24 hours. Efficiency of pipe ‘C’ = 72/24 = 3 units/hour. Required percentage = ((3 - 2)/2) × 100 = 50%. Final Answer: Pipe C is 50% more efficient than pipe B.
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