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Let the total capacity of the tank be 150 units Efficiency of pipe ‘A’ = 150/25 = 6 units/hour Efficiency of pipe ‘B’ = 150/30 = 5 units/hour Tank filled in 12 hours = 12 × 6 = 72 units Therefore, required time taken to fill the remaining tank = (150 – 72)/(6 – 5) = 78 hours Therefore, total time taken = 12 + 78 = 90 hours
Find the value of (cos 60 º + sin 60 º) /(tan 60 º + cot 45 º) .
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
If sin 28° = 15/17 , then tan 62° = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is: