Question
Pipe ‘A’ can fill a tank in 20 hours while pipe
‘B’ takes 40 hours to empty it. Pipe ‘A’ is opened alone when the tank was empty and after 10 hours pipe ‘B’ is also opened. In how much time will the tank get filled completely?Solution
Let the total capacity of the tank be 40 units Efficiency of pipe ‘A’ = 40/20 = 2 units/hour Efficiency of pipe ‘B’ = 40/40 = 1 units/hour Tank filled in 10 hours = 10 × 2 = 20 units Therefore, required time taken to fill the remaining tank = (40 – 20)/(2 – 1) = 20 hours Therefore, total time taken = 10 + 20 = 30 hours
More Pipes and cisterns Questions
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?20% of 240 + 18% of 200 = ?
140% of 9/8 of ? = 108% of 2800
5/13 × 104 + 1(2/9) × 198 = 133 + ?
12% of 152 + 12% of 150 = ? of 5
Find the Value of
3/4 of 2000 + √1024 = ? + 12.5% of 3200
108² + 99 X 98² =?
...2.4 of 7.2 of 1/57.6 of 4200 = ?
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