Question
Find the smallest number which when divided by 7 and 11
leaves a remainder of 5 in each case.Solution
If number = N, then N leaves remainder 5 when divided by 7 and 11. So N − 5 is divisible by both 7 and 11. LCM(7, 11) = 7 × 11 = 77 So N − 5 = 77 × 1 = 77 N = 77 + 5 = 82
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