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ATQ,
Since, 72 = 9 × 8
So, the given number must be divisible by both 9 and 8.
Divisibility by 8:
Last three digits of the number (a9b) must be divisible by 8.
For a = 4 and b = 8, the number "498" is divisible by 8.
Divisibility by 9:
Sum of the digits (6 + 3 + 4 + 9 + 8 = 30) must be divisible by 9, which it is not.
Adjusting the values, for a = 6 and b = 3, the number "693" is divisible by both.
Hence, a = 6, b = 3
And, a + 2b = 6 + 2 × 3 = 6 + 6 = 12
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