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ATQ,
Since, 72 = 9 × 8
So, the given number must be divisible by both 9 and 8.
Divisibility by 8:
Last three digits of the number (x2y) must be divisible by 8.
For x = 5 and y = 4, the number "524" is divisible by 8.
Divisibility by 9:
Sum of the digits (4 + 8 + 5 + 2 + 4 = 23) must be divisible by 9, which it is not.
Adjusting the values, for x = 3 and y = 6, the number "326" is divisible by both.
Hence, x = 3, y = 6
And, x - y = 3 - 6 = -3
If (x –1.3)3+(x–1.4)3+(x–1.5)3 = 3(x–1.3)(x–1.4)(x–1.5), Then x = ?
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If x + y + z = 20, x² + Y² + z² = 160 and x z = y², then find the value of x z?
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? + (35)² = (130)² - (45)² - 2850
In a best-of-two chess match between Player X and Player Y, the probability that Player X wins a game is (5/9), and the probability that Player Y loses ...