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ATQ,
Let the first number be 'x'
Therefore, the five consecutive odd numbers will be 'x', (x + 2), (x + 4), (x + 6), (x + 8)
ATQ:
x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 5 × 17
Or, 5x + 20 = 85
Or, 5x = 85 - 20
Or, 5x = 65
Or, x = 65 ÷ 5 = 13
Therefore, the first number = 13
So, the largest or the last number is = (x + 8) = 13 + 8 = 21
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