Question
What is the smallest number that should be added to 987
so that the sum is exactly divisible by 11?Solution
Find remainder when 987 is divided by 11. 11 × 89 = 979 Remainder = 987 − 979 = 8 To make it divisible by 11, we need remainder 0. So we must add (11 − 8) = 3. Sum = 987 + 3 = 990, which is divisible by 11.
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