Question
When the digits of a two-digit number are interchanged,
the new number becomes 23 more than 150% of the original number. If the sum of the digits is 8, find the original number.Solution
Let the unit digit and tens digit of the original number be ‘y’ and ‘x’, respectively.
Original number = (10x + y)
According to the data given:Â
10y + x = 1.5 × (10x + y) + 23
Multiplying both sides by 2,Â
20y + 2x = 30x + 3y + 46Â
⇒ 28x − 17y = −46 …. (I)
And, x + y = 8 …. (II)
From (II), x = 8 − y. Substitute in (I):Â
28(8 − y) − 17y = −46Â
224 − 45y = −46Â
45y = 270Â
y = 6
Then x = 2.Â
So, original number = 10 × 2 + 6 = 26.
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