Question
In a workshop of 50 participants, the average age is 40 years. One participant aged 38 leaves, and 5 new participants with an average age of 44 join. When the speaker’s age is also included, the average becomes 41 years. What is the age of the speaker?
Solution
Initial total age = 50 × 40 = 2000 years
Age of 5 new participants = 5 × 44 = 220 years Let the speaker’s age be ‘y’
New total age without speaker = 2000 - 38 + 220 + y = (2182 + y)
New total number of people = 50 - 1 + 5 + 1 = 55
New total age = 55 × 41 = 2255 years
So, speaker’s age = 2255 - 2182 = 73 years
More Average Questions
- The average salary of A, B and C is Rs. 22000 while average salary of B, C and D is Rs. 25000. If the average salary of D be 2 times of that of A, then the...
- The average of 5 numbers is 24. If one number is removed, the average of the remaining 4 numbers becomes 21. Find the number that was removed.
- Find the average of the following set scores. 450, 1050, 12, 390, 143, 286, 550, 999
- The average of 5 numbers is 32. The sum of four of them is 120. What is the fifth number ?
- The average expenditure of a man for the first 5 month is Rs.4000 and for the next 7 months is Rs.6000. If he saves 10000 in that year then find his averag...
- The average weight of 4 persons is 66 kg. The heaviest person’s weight is 32 kg more than the lightest person’s weight. If the average weight of the rest t...
- A number is such that when it is multiplied by 4, it gives another number which is as much above from 180 as the original number (itself) is below 180. The...
- In an examination, Aryan scored 54% marks and passed by 98 marks, while Rohit scored 35% marks and failed by 35 marks. Determine the passing marks for the ...
- The mean of 15 values is 72. The mean of the first seven values is 62, and the mean of the last five values is 86. The eighth value equals 25% of the ninth...
- Seven successive numbers have an average of 59. What is the total of their lowest and highest numbers?