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      Question

      Let ‘x’ be the least number divisible by 10, 14, 18,

      21 and 28, and also ‘x’ is a perfect square. Find the remainder when ‘x’ is divided by 85.
      A 30 Correct Answer Incorrect Answer
      B 71 Correct Answer Incorrect Answer
      C 26 Correct Answer Incorrect Answer
      D 42 Correct Answer Incorrect Answer

      Solution

      ATQ, LCM of 10, 14, 18, 21 and 28 = 1260 Since, 1260 = (2 × 2 × 3 × 3 × 5 × 7) To make it a perfect square, multiply by ‘5 × 7’ = 35. So, desired number = 1260 × 35 = 44100 44100 ÷ 85 = 518 × 85 + 30 So, desired remainder = 30

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