Question
How many numbers between 340 and 1260 are divisible by
both 18 and 24, but are not divisible by 5?Solution
If a number if multiple of 18 and 24, then it's a multiple of L.C.M of 18 and 24 = 72 Therefore, first and last multiple of 72 between 340 and 1260 are 360 and 1224, respectively Therefore, numbers are 360, 432, 504, ......, 1224 which is in arithmetic progression Therefore, first term (a) = 360, common difference (d) = 72 and nth term (an) = 1224 Therefore, an = a + (n - 1) X d Or, 1224 = 360 + (n - 1) X 72 Or, (n - 1) = (1224 - 360) ÷ 72 Or, n - 1 = 12 Or, n = 13 Now, numbers which are multiple of 72 and 5 both are 360, 720, 1080 i.e. 3 numbers Required number of multiples = 13 - 3 = 10Â
Statements: J < K, J < L, L > M
Conclusions: I. J < M II. L = J
...In which of the following expressions will the expression ‘D < F’ be definitely true?
Statement: C > S > F > B > L; I > B > T
Conclusion: I. I > L II. T < C
Three statements, showing relationship between different elements, are followed by three conclusions (I). (II) and (III). Assuming the statements to be ...
Statement: Q > R; O < K ≤ N; O ≥ S > R
Conclusion: I. O ≥ Q     II. R < N.
Statements: B > D > X > T ≤ N ≥ O = U
Conclusion
I: N > D
II: T > B
Statements: A > B > C, C < D > E, E = F > G
Conclusion:
I. C = G
II. A > F
In the question, assuming the given statements to be true, Find which of the conclusion (s) among given three conclusions is /are definitely true and ...
Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) to complete the given expression...
Statements: A > B > C; D < E < C; D ≥ F = G
Conclusion:
I. G < E
II. F < A