Question
Simica invested a certain amount of money at a simple
interest rate of 12.5% per annum and earned Rs. 2,400 as interest over 3 years. If Tabu invested the same amount at a compound interest rate of 10% per annum, compounded annually, how much interest would she earn in 3 years?Solution
Let the sum invested by Simica = Rs. 'Y'
Interest received by Simica = (Y X 12.5 X 3) ÷ 100 = 2400
So, Y = 2400 ÷ 0.375 = 6400
So, sum invested by Tabu = Rs. 6400
Interest received by Tabu = 6400 X {1 + (10/100)} 3 - 6400
= 6400 X 1.1 3 – 6400 = 8518.40 – 6400 = Rs. 2,118.40
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
Find the coefficient of x³ in (2x − 3)⁶.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
Find the value of 'x' and 'y' in the following equation:
7x - 2y = 46
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
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