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    Question

    The cube of the difference between two given natural

    numbers is 1000, while the product of these two given numbers is 56. Find the positive difference between the cubes of these two given numbers.
    A 4104 Correct Answer Incorrect Answer
    B 2680 Correct Answer Incorrect Answer
    C 2160 Correct Answer Incorrect Answer
    D 5626 Correct Answer Incorrect Answer

    Solution

    1st natural number = x 2nd natural number = y (x - y)3 = 1000 (x - y) = 3√1000 = 10         … (1) squaring both sides   (x - y) ² = 100 x2+y2-2xy =100 x² + y² = 100 + 112 = 212 Now, (x + y) = √ (x² + y² + 2xy) =√ (212 + 112) = √324 = 18  … (2) Now Eq (1) +Eq (2). x-y+x+y =10+18=28 2x =28 x=14 y=4 Now positive difference between the cubes= (14)3-(4)3 =2744-64 =2680.

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