Question
Two numbers differ by 8, and their product is 240. Find
the numbers.Solution
Let the numbers be x and y, with x > y. Weβre told: x β y = 8 xΒ·y = 240 From (1), x = y + 8. Plug that into (2): (y + 8)Β·y = 240 yΒ² + 8y = 240 yΒ² + 8y β 240 = 0 Now solve the quadratic: yΒ² + 8y β 240 = 0 We look for two numbers that multiply to β240 and add to +8. Those numbers are +20 and β12, because: 20 Γ (β12) = β240 20 + (β12) = 8 So we can factor: (y + 20)(y β 12) = 0 That gives two possible y values: y = β20 or y = 12 Now find x = y + 8 in each case: If y = 12 x = 12 + 8 = 20 Pair: (20, 12) If y = β20 x = β20 + 8 = β12 Pair: (β12, β20) Check both: 20 β 12 = 8 and 20 Γ 12 = 240 β (β12) β (β20) = 8 and (β12) Γ (β20) = 240 β Ignore the negatuive value we get, Final answer: The numbers are 20 and 12
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