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      Question

      Two numbers differ by 8, and their product is 240. Find

      the numbers.
      A 10 and 12 Correct Answer Incorrect Answer
      B 20 and 12 Correct Answer Incorrect Answer
      C 11 and 13 Correct Answer Incorrect Answer
      D 14 and 10 Correct Answer Incorrect Answer

      Solution

      Let the numbers be x and y, with x > y. We’re told: x βˆ’ y = 8 xΒ·y = 240 From (1), x = y + 8. Plug that into (2): (y + 8)Β·y = 240 yΒ² + 8y = 240 yΒ² + 8y βˆ’ 240 = 0 Now solve the quadratic: yΒ² + 8y βˆ’ 240 = 0 We look for two numbers that multiply to βˆ’240 and add to +8. Those numbers are +20 and βˆ’12, because: 20 Γ— (βˆ’12) = βˆ’240 20 + (βˆ’12) = 8 So we can factor: (y + 20)(y βˆ’ 12) = 0 That gives two possible y values: y = βˆ’20 or y = 12 Now find x = y + 8 in each case: If y = 12 x = 12 + 8 = 20 Pair: (20, 12) If y = βˆ’20 x = βˆ’20 + 8 = βˆ’12 Pair: (βˆ’12, βˆ’20) Check both: 20 βˆ’ 12 = 8 and 20 Γ— 12 = 240 βœ“ (βˆ’12) βˆ’ (βˆ’20) = 8 and (βˆ’12) Γ— (βˆ’20) = 240 βœ“ Ignore the negatuive value we get, Final answer: The numbers are 20 and 12

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