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    Question

    Find the sum of digits of the largest three-digit

    number that gives a remainder 2 when divided by 7, 9 and 11.
    A 20 Correct Answer Incorrect Answer
    B 28 Correct Answer Incorrect Answer
    C 75 Correct Answer Incorrect Answer
    D 36 Correct Answer Incorrect Answer

    Solution

    ATQ, LCM of (7, 9 and 11) = 693 Largest 3-digit number divisible by 693 = 693 ├Ч 1 = 693 So, N = 693 + 2 = 695 Sum of digits of 'N' = 6 + 9 + 5 = 20

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