Question
Find the sum of digits of the largest three-digit
number that gives a remainder 2 when divided by 7, 9 and 11.Solution
ATQ, LCM of (7, 9 and 11) = 693 Largest 3-digit number divisible by 693 = 693 × 1 = 693 So, N = 693 + 2 = 695 Sum of digits of 'N' = 6 + 9 + 5 = 20
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