Question
Find the least number which when divided by 8, 12 and 15
leaves remainder 5 each time.Solution
ATQ, Required number N satisfies: N − 5 is divisible by 8, 12, 15 So N − 5 = LCM(8,12,15) 8 = 2³, 12 = 2²×3, 15 = 3×5 LCM = 2³×3×5 = 120 So N = 120 + 5 = 125
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