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    Question

    The ratio between the sum of the digits of a two-digit

    number and that two-digit number is 1 : 6. If the digit in the unit's place is three less than the digit in the ten’s place, then find the 38% of the number.
    A 19.38 Correct Answer Incorrect Answer
    B 28.12 Correct Answer Incorrect Answer
    C 37.04 Correct Answer Incorrect Answer
    D 10.15 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let ten's digit and unit's digit be x and (x-3) respectively Sum of digits = x + (x-3) = 2x – 3 Let the number be 10x + (x-3) = 11x - 3 (2x – 3) / (11x – 3) = 1/6 12x – 18 = 11x – 3 x = 15 Number is 51 Required number = 51 * 38/100 = 19.38

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