Question
The ratio between the sum of the digits of a two-digit
number and that two-digit number is 1 : 6. If the digit in the unit's place is three less than the digit in the ten’s place, then find the 38% of the number.Solution
ATQ, Let ten's digit and unit's digit be x and (x-3) respectively Sum of digits = x + (x-3) = 2x – 3 Let the number be 10x + (x-3) = 11x - 3 (2x – 3) / (11x – 3) = 1/6 12x – 18 = 11x – 3 x = 15 Number is 51 Required number = 51 * 38/100 = 19.38
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