Question
'M' is the largest three-digit number that leaves 3 as a
remainder when divided by 9, 12 and 5, Find the sum of digits of 'M'.Solution
LCM of (9, 12 and 5) = 180 Largest 3 digit number that is divisible by 180 = 180 x 5 = 900 So, N = 900 + 3 = 903 So, sum of digits of 'N' = 9 + 0 + 3 = 12
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