New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Determine the smallest perfect square that is exactly

    divisible by 9, 15, 20, and 35. Then, find the remainder when this perfect square is divided by 88.
    A 53 Correct Answer Incorrect Answer
    B 81 Correct Answer Incorrect Answer
    C 30 Correct Answer Incorrect Answer
    D 24 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 9, 15, 20 and 35 = 1260

    Since, 1260 = (2 × 2 × 3 × 3 × 5 × 7)

    To make it a perfect square, multiply by (2 × 5 × 7) = 70

    So, required number = 1260 × 70 = 88200

    88200 ÷ 88 = 1002 × 88 + 24

    So, desired remainder = 24

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