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      Question

      Determine the smallest perfect square that is exactly

      divisible by 9, 15, 20, and 35. Then, find the remainder when this perfect square is divided by 88.
      A 53 Correct Answer Incorrect Answer
      B 81 Correct Answer Incorrect Answer
      C 30 Correct Answer Incorrect Answer
      D 24 Correct Answer Incorrect Answer

      Solution

      ATQ,

      LCM of 9, 15, 20 and 35 = 1260

      Since, 1260 = (2 ├Ч 2 ├Ч 3 ├Ч 3 ├Ч 5 ├Ч 7)

      To make it a perfect square, multiply by (2 ├Ч 5 ├Ч 7) = 70

      So, required number = 1260 ├Ч 70 = 88200

      88200 ├╖ 88 = 1002 ├Ч 88 + 24

      So, desired remainder = 24

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