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    Question

    Find the least number greater than 100 which leaves a

    remainder of 4 when divided by 5, 6, and 7.
    A 223 Correct Answer Incorrect Answer
    B 214 Correct Answer Incorrect Answer
    C 132 Correct Answer Incorrect Answer
    D 332 Correct Answer Incorrect Answer

    Solution

    We want N such that: N тЙб 4 (mod 5), N тЙб 4 (mod 6), N тЙб 4 (mod 7) Then (N тИТ 4) is divisible by 5, 6, and 7 LCM(5, 6, 7) = 2 ├Ч 3 ├Ч 5 ├Ч 7 = 210 So N тИТ 4 = 210k тЗТ N = 210k + 4 Smallest N > 100: For k = 1: N = 210 + 4 = 214 (> 100) Answer: 214

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