Question
If 59x284 is a six-digit number that is divisible by 3, then find the maximum value of 6x.
Solution
We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
5 + 9 + x + 2 + 8 + 4 = (28 + x) should be divisible by 3 So, possible values of x = 2, 5, 8 Maximum possible value of x = 8 So, required value
= 6 × 8
= 48
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