Question
A set ‘X’ includes four back-to-back even numbers,
and set ‘Y’ holds four successive odd numbers. The mean of the second elements from both sets is 38.5. Determine the total of the last numbers in both sets.Solution
ATQ,
Set X: {a, (a + 2), (a + 4), (a + 6)} Set Y: {b, (b + 2), (b + 4), (b + 6)} Now, (a + 2 + b + 2) ÷ 2 = 38.5 Or, a + b + 4 = 77 Or, a + b = 73 Required sum = a + 6 + b + 6 = 73 + 12 = 85
More No. System Questions
(11/12) × (18/22) × (4/3) + 3 = ?2
- What will come in the place of question mark (?) in the given expression?
32% of 74% of ? = 16% of 37% of 180 30% of 215 + 135% of ? = 469.5
800 + 900 X (3)-2 - ? = 25 X 60 ÷ 2
1555.5 + 1000.8 – 1354.3 = ? + 52
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? - 55% of 220 – 15% of 40 = 20% of ?
50 ÷ 2.5 × 64 + ? = 1520
(-251 × 21 × -12) ÷ ? = 158.13
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