Question
The number '24138p' is divisible by 6 but not by 5.
Determine the result of (p + 11).Solution
ATQ,
Divisible by 6 ⇒ divisible by 2 and 3.
Sum of digits = 2 + 4 + 1 + 3 + 8 + p = 18 + p
We want (18 + p) divisible by 3
p must be even and ≠ 0 or 5
Try p = 6 → 18 + 6 = 24
So, p = 6
(p + 11) = 6 + 11 = 17
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