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      Question

      Find the smallest natural number which when divided by

      ‘3’, ‘11’ and ‘13’, leaves a remainder ‘2’ in each case.
      A 431 Correct Answer Incorrect Answer
      B 429 Correct Answer Incorrect Answer
      C 430 Correct Answer Incorrect Answer
      D 428 Correct Answer Incorrect Answer

      Solution

      LCM of (3, 11 and 13) = 429 So, required number = 429 + 2 = 431

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