Question
In a particular examination, Cheenu achieved 48% of the
total marks and fell short by 72 marks to pass. On the other hand, Meenu obtained 68% of the total marks, which was 48 marks above the minimum required to pass. Determine the total marks available in this examination.Solution
Let the maximum marks of the exam be ‘100x’ Marks scored by Cheenu = 100x × 0.48 = ‘48x’ Marks scored by Meenu = 100x × 0.68 = ‘68x’ According to question: 48x + 72 = 68x – 48 Or, 68x – 48x = 72 + 48 Or, 20x = 120 Or, x = 6 Therefore, maximum marks of the exam = 100x = 100 × 6 = 600 Hence, option e.
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