Question
Find the smallest number which when divided by 7, 9 and
12 leaves remainder 5 in each case.Solution
ATQ, Let number be N. N - 5 is divisible by 7, 9, 12. LCM(7, 9, 12) = 2^2 * 3^2 * 7 = 497 = 252 So N - 5 = 252 N = 252 + 5 = 257
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