Question
Three numbers are in the ratio 5:7:11. If the difference
between the sum of the smallest and the largest number and the sum of the smallest and the second largest number is 24, then find the largest number.Solution
ATQ;
Let the three numbers be 5x, 7x, and 11x, respectively.
ATQ,
(5x+11x)−(5x+7x)=24
16x−12x=24
4x=24
x=6
Therefore, the largest number = 11x = 11 × 6 = 66
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