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      Question

      Three numbers are in the ratio 5:7:11. If the difference

      between the sum of the smallest and the largest number and the sum of the smallest and the second largest number is 24, then find the largest number.
      A 90 Correct Answer Incorrect Answer
      B 75 Correct Answer Incorrect Answer
      C 66 Correct Answer Incorrect Answer
      D 70 Correct Answer Incorrect Answer

      Solution

      ATQ;
      Let the three numbers be 5x, 7x, and 11x, respectively.
      ATQ,
      (5x+11x)βˆ’(5x+7x)=24
      16xβˆ’12x=24
      4x=24
      x=6
      Therefore, the largest number = 11x = 11 Γ— 6 = 66

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