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    Question

    Three numbers are in the ratio 5:7:11. If the difference

    between the sum of the smallest and the largest number and the sum of the smallest and the second largest number is 24, then find the largest number.
    A 90 Correct Answer Incorrect Answer
    B 75 Correct Answer Incorrect Answer
    C 66 Correct Answer Incorrect Answer
    D 70 Correct Answer Incorrect Answer

    Solution

    ATQ;
    Let the three numbers be 5x, 7x, and 11x, respectively.
    ATQ,
    (5x+11x)−(5x+7x)=24
    16x−12x=24
    4x=24
    x=6
    Therefore, the largest number = 11x = 11 × 6 = 66

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