Question
There are two sets: A has four consecutive even integers
and B has four consecutive odd integers. The average of the third term of A and the third term of B is 90.5. Find the sum of the last terms of both sets.Solution
ATQ, Set A: {p, (p + 2), (p + 4), (p + 6)} Set B: {q, (q + 2), (q + 4), (q + 6)} ((p + 4) + (q + 4)) ÷ 2 = 90.5 Or, (p + q + 8) ÷ 2 = 90.5 Or, p + q + 8 = 181 Or, p + q = 173 Required sum = (p + 6) + (q + 6) = p + q + 12 = 173 + 12 = 185
98    148    185    ?     228    238
5 29 ? 569 1703 3401
...(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
86 36 ? 7 7.5 0.75
7Â Â Â Â Â Â 15Â Â Â Â Â Â Â 31Â Â Â Â Â Â 63Â Â Â Â Â Â 127Â Â Â Â Â Â ?
...3601 3602 1803 604 154 36
...24 ? 14 16 39 88.5
...94, 563, 2813, ? 33743, 67481
A series is 2100, 3431, 2431, 3160, 2648, 2991
If another series 1728, __, __, __, __, p, follows the same pattern as the given number series, th...
12, 6, 6, 9, 18, ?