In a company, there are men, women, and boys working.

Solution

Let the no. of women in company = x

So, the no. of men in company = x*120/100 = 1.2x

And the no. of boys in company = x*60/100 = 0.6x

Now given that, 1.2x = 12 => x = 10

The no. of men, women and boys in the company is 1.2*10 = 12, 1*10 = 10 and 0.6x*10 = 6 respectively.

Let the share of a man = y

So, the share of a woman = 137.5y/100 = 1.375y

And the share of a boy = 162.5y/100 = 1.625y

Ratio between the share of a man, a woman and a boy = y: 1.375y: 1.625y = 8: 11: 13

The ratio between the shares of 12 men, 10 women and 6 boys-

=> 12*8: 10*11: 6*13

=> 96: 110: 78

=> 48: 55: 39

The share of 10 women = (55/142)*6390 = 2475

The share of 30 women = (2475/10)*30 = 7425

The share of 6 boys = (39/142)*6390 = 1755

The share of 30 boys = (1755/6)*30 = 8775

Required difference = 8775 - 7425 = 1350