Question
Find the sum of all those 3-digit numbers which when
divided by 10 leave a remainder of 5.Solution
Numbers 105, 115, 125, ……985, 995 first number (a) = 105 The last number (8) = 995 All difference (d) =10 From the formula, nth term (Tn) = a + (n-1) d, 995=105+(n-1) 10  n = 90  Sum of n terms (Sn) =n/2 [2a+(n-1) d]  90/2[2 ×105+ (90-1)10] = 45 [210+890] = 45 × 1100  = 49500.
More No. System Questions
Select the option figure that will come next in the following figure series.
Select the correct option that will meet the image pattern of the given image.
Which of the given figures when placed in the 5th position would continue the series that is established by the first four figures?
Identify the missing figure from the given options that completes the pattern.
What is water image of given figure?
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