Question
Find the difference between minimum and maximum value
of 'c' such that '5c4632' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '5c4632' = (5 + c + 4 + 6 + 3 + 2) = c + 20.
So, c + 20 should be divisible by 3.
Possible values of 'c' = 1, 4, 7
Minimum value of 'c' = 1
Maximum value of 'c' = 7
Required difference = 7 – 1 = 6Â
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