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    Question

    Find the difference between minimum and maximum value

    of 'c' such that '5c4632' is always divisible by 3.
    A 6 Correct Answer Incorrect Answer
    B 7 Correct Answer Incorrect Answer
    C 5 Correct Answer Incorrect Answer
    D 9 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '5c4632' = (5 + c + 4 + 6 + 3 + 2) = c + 20.
    So, c + 20 should be divisible by 3.
    Possible values of 'c' = 1, 4, 7
    Minimum value of 'c' = 1
    Maximum value of 'c' = 7
    Required difference = 7 – 1 = 6 

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