Question
Find the difference between minimum and maximum value
of 'c' such that '5c4632' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '5c4632' = (5 + c + 4 + 6 + 3 + 2) = c + 20.
So, c + 20 should be divisible by 3.
Possible values of 'c' = 1, 4, 7
Minimum value of 'c' = 1
Maximum value of 'c' = 7
Required difference = 7 – 1 = 6Â
What value should come in the place of (?) in the following questions?
√(60 + 82 + 101) * 5 = ?
√1936 + √3025 = ? % of 220
What will come in the place of question mark (?) in the given expression?
28 × 15 + 48% of ? = 780
[∛(91125/19683 )- ∛(3375/5832 ) ] × ∛(512/9261) = ? - √(484/3969)
If 1.123 × 3.211 = 3.122 + ______________, then the number in blank space is
(288 ÷ 12 + 15 × 5 + 124) = ?
What will come in the place of question mark (?) in the given expression?
(√676 of √144 ÷ 13) of 2400% = ?Â
`(256/6561)(1/4) = ?`
