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      Question

      Find the difference between minimum and maximum value

      of 'c' such that '5c4632' is always divisible by 3.
      A 6 Correct Answer Incorrect Answer
      B 7 Correct Answer Incorrect Answer
      C 5 Correct Answer Incorrect Answer
      D 9 Correct Answer Incorrect Answer

      Solution

      A number is divisible by 3 when the sum of its digits is divisible by 3.
      Sum of digits of '5c4632' = (5 + c + 4 + 6 + 3 + 2) = c + 20.
      So, c + 20 should be divisible by 3.
      Possible values of 'c' = 1, 4, 7
      Minimum value of 'c' = 1
      Maximum value of 'c' = 7
      Required difference = 7 тАУ 1 = 6┬а

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