Question
Find the difference between minimum and maximum value
of 'd' such that '7d5289' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '7d5289' = (7 + d + 5 + 2 + 8 + 9) = d + 31.
So, d + 31 should be divisible by 3.
Possible values of 'd' = 2, 5, 8
Minimum value of 'd' = 2
Maximum value of 'd' = 8
Required difference = 8 – 2 = 6
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