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    Question

    Find the difference between minimum and maximum value

    of 'd' such that '7d5289' is always divisible by 3.
    A 6 Correct Answer Incorrect Answer
    B 8 Correct Answer Incorrect Answer
    C 9 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '7d5289' = (7 + d + 5 + 2 + 8 + 9) = d + 31.
    So, d + 31 should be divisible by 3.
    Possible values of 'd' = 2, 5, 8
    Minimum value of 'd' = 2
    Maximum value of 'd' = 8
    Required difference = 8 – 2 = 6

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