Question
Find the difference between minimum and maximum value
of 'e' such that '3e1750' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '3e1750' = (3 + e + 1 + 7 + 5 + 0) = e + 16.
So, e + 16 should be divisible by 3.
Possible values of 'e' = 2, 5, 8
Minimum value of 'e' = 2
Maximum value of 'e' = 8
Required difference = 8 – 2 = 6
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