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      Question

      Find the difference between minimum and maximum value

      of 'f' such that '2f4896' is always divisible by 3.
      A 8 Correct Answer Incorrect Answer
      B 7 Correct Answer Incorrect Answer
      C 6 Correct Answer Incorrect Answer
      D 5 Correct Answer Incorrect Answer

      Solution

      A number is divisible by 3 when the sum of its digits is divisible by 3.
      Sum of digits of '2f4896' = (2 + f + 4 + 8 + 9 + 6) = f + 29.
      So, f + 29 should be divisible by 3.
      Possible values of 'f' = 2, 5, 8
      Minimum value of 'f' = 2
      Maximum value of 'f' = 8
      Required difference = 8 โ€“ 2 = 6

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