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    Question

    Find the difference between minimum and maximum value

    of 'f' such that '2f4896' is always divisible by 3.
    A 8 Correct Answer Incorrect Answer
    B 7 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '2f4896' = (2 + f + 4 + 8 + 9 + 6) = f + 29.
    So, f + 29 should be divisible by 3.
    Possible values of 'f' = 2, 5, 8
    Minimum value of 'f' = 2
    Maximum value of 'f' = 8
    Required difference = 8 – 2 = 6

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