Question
Find the remainder when (5)100 is divided by
7Solution
ATQ, By Fermat's Little Theorem, since 7 is prime, we have: 56 = 1(mod 7) Thus, 5100 = 5(6×16+4) = (56)16 × 54 = 116 × 54 = 54 (mod 7) 52 = 25 = 4 (mod 7) 54 = (52)2 = 16 = 2 (mod 7) Thus, the remainder is 2 .
Calculate the value of x2,  if [(8 + 62) ÷ 4 of x + 2.5 × 5 = 42 + 20% of 10].
√ (12+√ (12+√ (12+ ⋯ ∞ ))Â
648 ÷ 36 × 49 – 1012 + 847 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
12.232 + 29.98% of 539.99 = ? × 5.99
- What will come in place of (?) in the given expression.
(14)² – (12)² = ? 1/6+ 999*53/54 ×9 = ?
33 × 5 - ?% of 250 = 62 - 6
323 × 15 + (?)² = 4989
13 X √? + 256 ÷ 4 = 30% of 900 - 50