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    Question

    Find the number of 5-digit numbers that can be formed

    using digits 0–9 without repetition and divisible by 5.
    A 5252 Correct Answer Incorrect Answer
    B 5712 Correct Answer Incorrect Answer
    C 4520 Correct Answer Incorrect Answer
    D 4460 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Last digit = 0 or 5. Case 1: last = 0 β†’ first digit β‰  0 β†’ 9 choices; remaining 3 = P(8,3)=336 β†’ 9Γ—336=3024 Case 2: last = 5 β†’ first β‰  0,5 β†’ 8 choices; remaining 3 = P(8,3)=336 β†’ 8Γ—336=2688 Total = 3024+2688 = 5712

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