Question
Find the number of 5-digit numbers that can be formed
using digits 0–9 without repetition and divisible by 5.Solution
ATQ,
Last digit = 0 or 5. Case 1: last = 0 → first digit ≠ 0 → 9 choices; remaining 3 = P(8,3)=336 → 9×336=3024 Case 2: last = 5 → first ≠ 0,5 → 8 choices; remaining 3 = P(8,3)=336 → 8×336=2688 Total = 3024+2688 = 5712
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