Question
Group ‘M’ comprises four even integers in order, and
group ‘N’ includes four successive odd integers. If the average of their first elements is 33.5, what is the sum of the last elements of both groups?Solution
ATQ,
Group M: {x, (x + 2), (x + 4), (x + 6)} Group N: {y, (y + 2), (y + 4), (y + 6)} Now, (x + y) ÷ 2 = 33.5 Or, x + y = 67 Required sum = x + 6 + y + 6 = 67 + 12 = 79
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