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      Question

      The combined number of apples with John and Paul is 10 more

      than the number with George. Also, Paul and George together have 6 more apples than John. If John and George together have 38 apples, how many apples do they have in all?
      A 25 Correct Answer Incorrect Answer
      B 46 Correct Answer Incorrect Answer
      C 65 Correct Answer Incorrect Answer
      D 75 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let apples with John = x, Paul = y, George = zThen:

      x + y = z + 10 ………(1)

      y + z = x + 6 ………(2)

      x + z = 38 ………(3)

      Add (1), (2), and (3):

      → (x + y) + (y + z) + (x + z) = z + 10 + x + 6 + 38

      → 2x + 2y + 2z = x + z + 54

      → 2(x + y + z) = x + z + 54

      → From (3), x + z = 38

      → 2(x + y + z) = 38 + 54 = 92

      → x + y + z = 46

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