Question
The combined number of apples with John and Paul is 10 more
than the number with George. Also, Paul and George together have 6 more apples than John. If John and George together have 38 apples, how many apples do they have in all?Solution
ATQ,
Let apples with John = x, Paul = y, George = zThen:
x + y = z + 10 ………(1)
y + z = x + 6 ………(2)
x + z = 38 ………(3)
Add (1), (2), and (3):
→ (x + y) + (y + z) + (x + z) = z + 10 + x + 6 + 38
→ 2x + 2y + 2z = x + z + 54
→ 2(x + y + z) = x + z + 54
→ From (3), x + z = 38
→ 2(x + y + z) = 38 + 54 = 92
→ x + y + z = 46
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