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    Question

    Find the digit sum of the largest three-digit number that

    leaves 1 as a remainder when divided by 8, 6, and 10.
    A 24 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 28 Correct Answer Incorrect Answer
    D 12 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of (8, 6, and 10) = 120

    Largest 3-digit number divisible by 120 = 120 × 8 = 960

    So, N = 960 + 1 = 961

    Sum of digits of 'N' = 9 + 6 + 1 = 16

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