📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      Find the digit sum of the largest three-digit number that

      leaves 1 as a remainder when divided by 8, 6, and 10.
      A 24 Correct Answer Incorrect Answer
      B 16 Correct Answer Incorrect Answer
      C 28 Correct Answer Incorrect Answer
      D 12 Correct Answer Incorrect Answer

      Solution

      ATQ,

      LCM of (8, 6, and 10) = 120

      Largest 3-digit number divisible by 120 = 120 × 8 = 960

      So, N = 960 + 1 = 961

      Sum of digits of 'N' = 9 + 6 + 1 = 16

      Practice Next
      More No. System Questions

      Relevant for Exams:

      ask-question