Question
Find the smallest 3‑digit number which is exactly divisible by both 12 and 15.
Solution
LCM(12, 15): 12 = 2² × 3 15 = 3 × 5 LCM = 2² × 3 × 5 = 4 × 3 × 5 = 60 We need smallest multiple of 60 which is ≥ 100. 60 × 1 = 60 60 × 2 = 120 So required number = 120. Answer: 120.
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