Find the number of zeroes in the product of 20 ×21× 22× ........× 40?
Alternate Method :
Product =20 × 21 × 22 × ........ × 40 .
So we can find number of zeroes in 40! then we can subtract number of zeroes in 19! .
So 40/5 = 8 and 8/5 = 1 and adding all quoitent, number of zeroes = 8+1= 9;
19/5 = 3, so number of zeroes in 19! = 3.
So number of zeroes in the given product =20 × 21 × 22 × ........ × 40 = 9 - 3 = 6.
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