Question
Find the smallest number that, when divided by 6, 8, and
12, leaves a remainder of 5 in each case.Solution
The required number is of the form LCM(6, 8, 12) + 5. LCM of 6, 8, and 12 = 24. The number = 24 + 5 = 29, 48+5 = 53, 72+5 = 77 Correct Option: c
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