Question
If 'x' is the smallest positive integer divisible by 9,
15, and 28, then determine the second smallest positive integer that is divisible by all three of these numbers.Solution
Lowest positive integer divisible by 9, 15 and 28 = LCM (9, 15, 28) So, LCM of (9, 15, and 28) = 22 X 32 X 51 X 71 = 1260 Therefore, the next larger number which is divisible by all the three given numbers = 2 X 1260 = 2520
What is the primary objective of RBI’s local cloud data storage pilot program launching in 2025?
________________ received 1st prize in the Ispat Rajbhasha Award for 2018-19 and 2020-21 and the Ispat Rajbhasha Prerna Award for 2019-20 in the meeting...
Who launched the 'Northeast Odyssey' motorcycle expedition in October 2024?
What is the main purpose of the amendment to Rule 8 of the Securities Contracts (Regulation) Rules, 1957?
What is India’s key focus area within the Sendai Framework for Disaster Risk Reduction, as highlighted by Principal Secretary P.K. Mishra?
Regarding the Telecom Design Collaboration Sprint by the DoT, consider the following statements:
A) The initiative was aimed at developing a tele...
How much did the State Bank of India raise through its tier 2 bond issue for FY25?
Who partnered with the State Bank of India (SBI) for the 'Grow with the Trees' drive in Srinagar?
What was the objective of Exercise Poorvi Lehar conducted by the Indian Navy on the East Coast?
The Union Health Ministry has introduced a new treatment for multidrug-resistant tuberculosis (MDR-TB). What is it called?
Relevant for Exams:
