Question
If 'x' is the lowest positive integer divisible by 12,
25 and 30, then find the second smallest positive integer which is divisible by all the three given numbers?Solution
Lowest positive integer divisible by 12, 25 and 30 = LCM (12, 25, 30) So, LCM of (12, 25, and 30) = 2² × 3¹ × 5² = 300 Therefore, the next larger number which is divisible by all the three given numbers = 2 × 300 = 600
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