📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    If 'x' is the lowest positive integer divisible by 12,

    25 and 30, then find the second smallest positive integer which is divisible by all the three given numbers?
    A 600 Correct Answer Incorrect Answer
    B 900 Correct Answer Incorrect Answer
    C 1200 Correct Answer Incorrect Answer
    D 1500 Correct Answer Incorrect Answer

    Solution

    Lowest positive integer divisible by 12, 25 and 30 = LCM (12, 25, 30) So, LCM of (12, 25, and 30) = 2² × 3¹ × 5² = 300 Therefore, the next larger number which is divisible by all the three given numbers = 2 × 300 = 600

    Practice Next
    More Divisibility rules Questions

    Relevant for Exams:

    ask-question